They’re coding for each possible option instead of making the code general and more concise

34

private bool IsEven(int number){ return not ((bool) (number & 1))

15

Modular division exists. Less sarcastically you can divide by 2 for a remainder to check every possible even or odd case

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I don’t even know this language but it seems pretty self explanatory. If a number “IsEven”, it will be true, otherwise it is false

12

You have to be baiting

9

The fact it’s Yan dev makes this even better, OP you might not know but dude is infamous for being dog water with code

8

Jus divide by 2 if the remainder is zero then true if not then false so it would be this symbol % when programming and you can use a condensed version of that

6

there’s plenty of atrocious things you could do in C, but whoever did that definitely did it as a joke

4

You could literally just use the modular operator to check if a number is even or odd and return an outcome based on that. Like in coding if you basically take a number and tell it to evaluate if the remainder of that number divided by 2 is 0 then that number is even

1